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target/arm: Define ID_AA64ZFR0_EL1 

Given that the only field defined for this new register may only
be 0, we don't actually need to change anything except the name.

Reviewed-by: Peter Maydell <peter.maydell@linaro.org>
Tested-by: Laurent Desnogues <laurent.desnogues@gmail.com>
Signed-off-by: Richard Henderson <richard.henderson@linaro.org>
Message-id: 20181005175350.30752-2-richard.henderson@linaro.org
Signed-off-by: Peter Maydell <peter.maydell@linaro.org>
master
Richard Henderson 2018-10-08 14:55:02 +01:00 committed by Peter Maydell
parent e5ae4d0c06
commit 9516d7725e
1 changed files with 2 additions and 1 deletions
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3
target/arm/helper.c
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@ -5018,9 +5018,10 @@ void register_cp_regs_for_features(ARMCPU *cpu)
.opc0 = 3, .opc1 = 0, .crn = 0, .crm = 4, .opc2 = 3,
.access = PL1_R, .type = ARM_CP_CONST,
.resetvalue = 0 },
{ .name = "ID_AA64PFR4_EL1_RESERVED", .state = ARM_CP_STATE_AA64,
{ .name = "ID_AA64ZFR0_EL1", .state = ARM_CP_STATE_AA64,
.opc0 = 3, .opc1 = 0, .crn = 0, .crm = 4, .opc2 = 4,
.access = PL1_R, .type = ARM_CP_CONST,
/* At present, only SVEver == 0 is defined anyway. */
.resetvalue = 0 },
{ .name = "ID_AA64PFR5_EL1_RESERVED", .state = ARM_CP_STATE_AA64,
.opc0 = 3, .opc1 = 0, .crn = 0, .crm = 4, .opc2 = 5,