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json-lexer: fix flushing logic to not always go to error state 

Currently we flush the lexer by passing in a NULL character. This
generally forces the lexer to go to the corresponding TERMINAL() state
for whatever token type it is currently parsing, emits the token to the
parser, then puts the lexer back into IN_START state. However, since a
NULL character causes char_consumed to be 0, we always do a second pass
after this, which puts us in the IN_ERROR state. Fix this behavior by
adding a "flush" flag that tells the lexer not to do a more than 1
iteration.

Signed-off-by: Michael Roth <mdroth@linux.vnet.ibm.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>
master
Michael Roth 2011-06-01 12:14:57 -05:00 committed by Anthony Liguori
parent 529a0ef5f3
commit bd3924a33a
1 changed files with 3 additions and 3 deletions
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6
json-lexer.c
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@ -274,7 +274,7 @@ void json_lexer_init(JSONLexer *lexer, JSONLexerEmitter func)
lexer->x = lexer->y = 0;
}
static int json_lexer_feed_char(JSONLexer *lexer, char ch)
static int json_lexer_feed_char(JSONLexer *lexer, char ch, bool flush)
{
int char_consumed, new_state;
@ -313,7 +313,7 @@ static int json_lexer_feed_char(JSONLexer *lexer, char ch)
break;
}
lexer->state = new_state;
} while (!char_consumed);
} while (!char_consumed && !flush);
/* Do not let a single token grow to an arbitrarily large size,
* this is a security consideration.
@ -335,7 +335,7 @@ int json_lexer_feed(JSONLexer *lexer, const char *buffer, size_t size)
for (i = 0; i < size; i++) {
int err;
err = json_lexer_feed_char(lexer, buffer[i]);
err = json_lexer_feed_char(lexer, buffer[i], false);
if (err < 0) {
return err;
}